Interested in advertising on Derpibooru? Click here for information!
Help fund the $15 daily operational cost of Derpibooru - support us financially!
Description
No description provided.
Help fund the $15 daily operational cost of Derpibooru - support us financially!
No description provided.
It’s true that in a set with just one element then 0 = 1 (trivial), but the contrary is true only in a ring. In short, if a(b + c) = ab + ac.
Rings are what people naturally think about when dealing with addition and multiplication.
If the elements are the zero
n=n+0=n+1 -> all the elements in the set are n
n=n1=n0=0 -> all the elements in the set are 0
Unless n0 != 0.
Maybe? I haven’t done math since college.
Well, in Mathematics “equal” is always relative to a symmetrical, reflexive and transitive relation, so we have something to start with. Nothing prevents you to change the definition in your context, but that would be a mess.
But “0” and “1” aren’t always what people used to think they are, i.e. the first natural number and its successor. If you define two binary operations in a set of elements, and call them “addition” and “multiplication”, then “0” and “1” can be defined as the neutral elements of those operations, respectively. If the elements are the same, then 0 = 1.
Or equal.
It depends on how you define 0 and 1.
I thought you learnt that lesson.
Objection overruled.