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I think you’re confusing it with computer floating-point maths, where signed zero exist. There, 1/−0 = −∞ and 1/+0 = +∞. Also, −1/−0 = +∞ and −1/+0 = −∞.
Edited
Read my previous post. You have to define it as a limit; we cannot have zero as a divisor defined as anything BUT a limit, which depends upon the “direction” from which you’re approaching.
If you haven’t covered limits and/or differential equations, it’s a little more advanced, and not as straightforward as ‘basic’ math.
Actually, x/0 is defined as ∞ or -∞, depending on whether x is greater or lesser than 0.
When x = 0 is when things get hairy. 0/0 literally is undefined; there is no number set that contains it.
That would make sense, it would be 0.00 repeating for infinity. You would make a nothing into an infinite of nothings just to show how much of a nothing you are trying to use to divide something… I think?
Not quite. If we stick to real numbers (e.g. let x ∈ ℝ), we can write the ‘solution’ as two distinct limits: one approaching from the positive direction, the other from the negative. They approach ±∞ (positive and negative infinity), respectively.
Otherwise, the answer is literally “undefined”.
as far as i understand.
The Smaller the Number you Divide through the Bigger the Solution.
2 / 1 = 2
2 / 0.5 = 4
2 / 0.25 = 16
soo
2 / 0 = ∞ ?
That’s how iris died
Only in theory. they allow calculators to do it as an exception, but the actual concept of dividing by nothing is pretty good. It would sort of be like trying to cut a pizza with a void.
your current filter.Division by Zero is Possible.