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Also:
x, y := 4, 4
y + 0 = x
x > y
x, y := 6, 9
y + (-3) = x
x > y
Oops?
You forgot to say that
that number
must be greater than0
.And first you need to prove that 1 + 1 even equals 2 if you’re going to take that route.
HI PEWDIE!
Everything is sexier in French.
Bitches if you may….
From the definition of addition s(0) + s(0) = s(0 + s(0)). Axiomatically, for all x, x + 0 = x. From this, 0 + 0 = 0, and if 0 + x = x, then 0 + s(x) = s(0 + x) = s(x), and so 0 + x = 0 for all x. Thus, 1 + 1 = s(0) + s(0) = s(0 + s(0)) = s(s(0)) = 2. For any numbers x and y, x > y only if there exists a number such that y + that number = x. Since 1 + 1 = 2, 2 > 1.
two is greater than one!
But 2 dodges and counterattacks combined 1 with an arrow blast.
A croissant would have been more appropriate but suuure lets go with banana o_0
And 4 + 1 = MOO
I think you meant to say 2+2 = fish