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This feels like making a guide to Rubik’s Cube, there are even formula for each case!
 
Except that this is a directed graph that doesn’t have enough structure to be a group, so it’s not a Cayley Graph (unlike the graph of the state space of Rubik’s Cube).
 
Proof: Suppose it is a Cayley Graph, then there is a unique identity element.  
Then blr is the identity element, since it takes you from START to START.  
However, blr takes you from right-lake to three-trees, therefore blr is not the identity element.  
Therefore, it is not a Cayley Graph.

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