rarararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararararara-  

@Background Pony #0BBB  
Ah! Yes, your right. I was referring “Ra” as a singular variable as stated below. So:
 
(Ra ¹)(Ra ²) = Ra ³
 
 
So disregard that last line.

@drumpowa  
Hold on! You just broke your own rule.
 
You said (x ^a) (x ^b) = x ^a+b
 
so it should mean that (x ^Ra)(X ^RaRa) = x ^{Ra + RaRa}
 
to go x ^RaRaRa you’d have to go (x ^Ra) ^RaRa

@FancyCat2008  
What? No.  
Even when you assumed that Ra = 1 and Rara = 2.  
Then in that case Ra + Rara != RaRaRa  
because Ra + Rara = 3, while RaRaRa = 2

@Background Pony #AD0D  
Even if they are the same variable it go as such and@FancyCat2008, pay attention:
 
Ra = Ra ¹
 
Rara = Ra ²
 
So if you know your algebra, you know how this goes.
 
|| If you don’t know or somehow forgot its (x ^a) (x ^b) = x ^a+b ||
 
||If you still can’t put two and two together, (x ^Ra)(x ^Rara) = x ^Rarara Then take the log _X on both sides gives you: (Ra) (Rara) = Rarara. ||

ra rara rarara

Ra-Rarara Ra-Rara! Super Hoof of the Nose Hair! ;3

@FancyCat2008  
Assuming Ra and Rara are different variables, It would be:  
Ra X Rara = (Ra)(Rara) = RaRara  
We need more horse math.

@Background Pony #7791  
Spike doesn’t have wings.

winged dragon of Rarity!

Shouldn’t it be “Ra + RaRa = Rarara?”
 
1 x 2 is still only 2.